From 568374d8cbe5f8a975e05089d5517c260566bb07 Mon Sep 17 00:00:00 2001
From: Giovanni Bussi <giovanni.bussi@gmail.com>
Date: Wed, 24 Jul 2019 12:53:30 +0200
Subject: [PATCH] fix

---
 user-doc/tutorials/aa-lugano-6b.txt | 8 ++++----
 1 file changed, 4 insertions(+), 4 deletions(-)

diff --git a/user-doc/tutorials/aa-lugano-6b.txt b/user-doc/tutorials/aa-lugano-6b.txt
index 6dcdf4cf9..119bb72db 100644
--- a/user-doc/tutorials/aa-lugano-6b.txt
+++ b/user-doc/tutorials/aa-lugano-6b.txt
@@ -137,14 +137,14 @@ Below you can find reference results
 \subsection lugano-6b-ex-4 Exercise 4: Standard affinity
 
 Now use the weights that you computed in the previous exercise to
-compute the standard affinity of the Mg to the phosphate. In order to do
+compute the absolute binding affinity of the Mg to the phosphate. In order to do
 so you should compute the relative probability of seeing the Mg bound to the phosphate
-and in the bulk region.
+and in the bulk region and normalize to 1 mol/M concentration.
 
-For instance, if you define bulk the region between 1.5 and 2.5 angstrom, you should multiply the 
+For instance, if you define bulk the region between 1.5 and 2.5 angstrom, you should divide the 
 weight of the unbound state by a factor \f$ \frac{4\pi}{3}(2.5^3-1.5^3)/V_{mol} \f$
 where \f$V_{mol}=1.66\f$ is the volume corresponding to the inverse of 1 mol/L concentration.
-
+The absolute binding affinity is then defined as \f$-k_BT \log \frac{w_B}{w_U} \f$.
 You should obtain a value of approximately 50.4 kj/mol
 
 \warning The trajectory is too short (approx 20ns) to obtain converged results!
-- 
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